1. Constructor Overloading practice program-1
This program demonstrates constructor overloading by creating objects with different constructors. It initializes student details using both the default and parameterized constructors.
class Student {
int id;
String name;
Student() {
id = 101;
name = "Rahul";
}
Student(int id, String name) {
this.id = id;
this.name = name;
}
void display() {
System.out.println("Student ID : " + id);
System.out.println("Student Name : " + name);
}
public static void main(String[] args) {
Student s1 = new Student();
Student s2 = new Student(102, "Priya");
System.out.println("Default Constructor:");
s1.display();
System.out.println("\nParameterized Constructor:");
s2.display();
}
}
Output:
Default Constructor:
Student ID : 101
Student Name : Rahul
Parameterized Constructor:
Student ID : 102
Student Name : PriyaCode language: PHP (php)2. Constructor Overloading practice program-2
This program calculates the area of a square and a rectangle using overloaded constructors. Different constructors initialize the required dimensions.
class Area {
Area(int side) {
System.out.println("Area of Square = " + (side * side));
}
Area(int length, int breadth) {
System.out.println("Area of Rectangle = " + (length * breadth));
}
public static void main(String[] args) {
Area square = new Area(5);
Area rectangle = new Area(8, 4);
}
}
Output:
Area of Square = 25
Area of Rectangle = 323. Method Overloading practice program-1
This program demonstrates method overloading by adding different numbers of arguments. The compiler selects the appropriate method based on the method parameters.
class Addition {
void add(int a, int b) {
System.out.println("Sum = " + (a + b));
}
void add(int a, int b, int c) {
System.out.println("Sum = " + (a + b + c));
}
void add(double a, double b) {
System.out.println("Sum = " + (a + b));
}
public static void main(String[] args) {
Addition obj = new Addition();
obj.add(10, 20);
obj.add(10, 20, 30);
obj.add(12.5, 7.5);
}
}Output:
Sum = 30
Sum = 60
Sum = 20.04. Method Overloading practice program-2
This program finds the maximum value using overloaded methods. The appropriate method is selected based on the number of arguments passed.
class Maximum {
int max(int a, int b) {
if (a > b)
return a;
else
return b;
}
int max(int a, int b, int c) {
if (a > b && a > c)
return a;
else if (b > c)
return b;
else
return c;
}
public static void main(String[] args) {
Maximum obj = new Maximum();
System.out.println("Maximum of Two Numbers = " + obj.max(25, 40));
System.out.println("Maximum of Three Numbers = " + obj.max(25, 40, 35));
}
}Output:
Maximum of Two Numbers = 40
Maximum of Three Numbers = 40